If sin(a+b)=1 and sin(a-b)=1/2 find a and b
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Answer:
Given that,
sin(a+b)=1
=)sin(a+b)=sin 90°
=)a+b=90°...................(i)
sin(a-b)=1/2
=) sin(a-b)=sin30°
=) a-b=30°....................(ii)
(i)+(ii)
=) a+b+a-b=90°+30°
=)2a=120°
=)a=120°/2
=)a=60°
putting a value in equation (i)
a+b=90°
=)60°+b=90°
=)b=90°-60°
=)b=30°
a=60° , b=30°
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