If sin (A + B) = 1, coB(A– B) = 1 and O' < A + B < 90°, find A and B
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Answer:
A = 45° and B = 45°.
Step-by-step explanation:
sin (A + B)= 1 or sin (A + B) = sin 90° [As sin 90° = 1] A + B = 90° …(1) Again, Cos(A-B) = 1 = cos 0° A – B = 0 …(2) Adding (1) and (2), we get 2A = 90° or A = 45° Putting A = 45° in (1) we get 45° + B = 90° or B = 45° Hence, A = 45° and B = 45°.
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