if sin(A+B) =1/root2 and
cos(A-B)= 1/root2,
then find <B.
Answers
Answered by
10
sin(A+B)=1/√2
sin(45°)=1/√2
sin(45°)=sin(A+B)
A+B=45°
cos(A-B)=1/√2
cos (45°)=1/√2
cos(45°)=cos (A-B)
A-B=45°
A+B+A-B=45+45
2A=90
A=90/2=45
A=45
B=0
(A,B)=45,0
hope helped!!!
sin(45°)=1/√2
sin(45°)=sin(A+B)
A+B=45°
cos(A-B)=1/√2
cos (45°)=1/√2
cos(45°)=cos (A-B)
A-B=45°
A+B+A-B=45+45
2A=90
A=90/2=45
A=45
B=0
(A,B)=45,0
hope helped!!!
HappiestWriter012:
certify my answer
Answered by
4
sin(A+B)=1/√2
sin(45°)=1/√2
sin(45°)=sin(A+B)
A+B=45°
cos(A-B)=1/√2
cos (45°)=1/√2
cos(45°)=cos (A-B)
A-B=45°
A+B+A-B=45+45
2A=90
A=90/2=45
A=45
B=0
(A,B)=45,0
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