Question

if sin(a+b)=1andcos(a-b)=√3/2 find aand b​

Answer 1

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sin(A+B)= 1

cos(A-B)=√3/2

From the trigonometric table of values, we know that

sin90°= 1

And cos30°=√3/2

Therefore,

A+B= 90-------(1)

A-B= 30--------(2)

Adding (1) and (2),

2A=120

A=60

Substituting A=60 in eq(1),

60+B=90

B=90-60

B=30

Answer: A=60° and B=30°

Answer 2

HEY MATE

given here

sin(a+b)=1

==>sin(a+b)=sin90°)

==>a+b=90. ...... (2)

and

cos(a-b)=root (3)/2

==>cos(a-b)=cos(30°)

==>a-b=30. ....(1)

now.

eq^n (1)+(2)

==>2a=120

==>a=60

and .

==>b=30

thus:-

a=60°,b=30°.

I hopes its helps u.

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