Question

If sin(A+B) = √3/2 and cos(A- B) = √3/2, 0°< A + B <90°, find the value of A and B​

Answer 1

Step-by-step explanation:

Sin(a+b) = √3/2

i.e.Sin 60°=√3/2

a+b= 60

b= 60-a .........(.1 )

Then,Cos(a-b) =√3/2

i.e.cos 30°= √3/2

a-b=30

from equation 1, we get

2a = 90°

a = 45°

and b= 15°