Question

If sin(A+B)=3√2 and cos(A−B)=3√2 then A=​

Answer 1

Answer:

sorrry ur question is wrong the question will be

(Q) sin(A+B)=√3/2and cos(A-B)=√3/2 then A=?

Step-by-step explanation:

explanation:

sin(A+B)=√3/2

=> sin(A+B)= sin60⁰( both the sin will be cut)

=>A+B=60⁰(I)

cos(A-B)=√3/2

=>cos(A-B)= cos30⁰(both the cos will be cut)

=>A-B=30⁰(II)

Adding both (I) and (II)

A+B=60⁰

+A-B=30⁰

After adding both +B and -B will be cut so the solution will be

=>2A=90⁰(since A+A=2A)

=>A=90⁰/2

=>A=45⁰

therefore, answer is A=45⁰