Question

If sin a+b=√3/2 and cos a-b=√3/2 where 0 b find a and b

Answer 1

sin(A+B)=1

cos(A-B)=√3/2

We know sin-¹ =90

A+B=9 _ _ _ _(1)

cos (A-B)=root 3/2

A-B=cos-¹ root 3/2

We know cos-¹ root 3/2=30

A-B=30 _ _ _ _ _ (2)

Solve (1) & (2)

A+B=90

A-B=30 add

2A=120

A=60 B=30

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