Question

if sin(A+B)=√3/2 and sin (A-B)=1/2 find the value of a and b​

Answer 1

Answer:

the value of a=45° and b=15°

Step-by-step explanation:

sin(A+B)=√3/2.

sin(A+B)=sin 60°.

cut sin in both side.

A+B=60°.  This is the first equation.

sin(A-B)=1/2.

sin(A-B)=sin 30°.

cut sin in both side.

A-B=30°.

equating equation first and second.

then we get a=45° and b=15°.