Question

if sin(A+B) = √3/2 and tan A= 1 find the values of A and B​

Answer 1

sin 60= ✓3/2

tan 45= 1

I have taken directly

it may help to you

Answer 2

The values of A = 45° and B = 15°

Given:

sin(A+B) = √3/2  and tan A= 1

To find:

Find the value of A and B

Solution:

From Trigonometric values table  

sin 60° = √3/2 and tan 45° = 1

(Use these values to solve the given question)

Given  sin(A+B) = √3/2 and tan A= 1

From above formulas

sin(A+B) = sin 60°  

⇒ A + B = 60° -----(1)

tan A = tan 45°

⇒  A = 45°

Now substitute A = 45° in (1)

⇒ 45° + B = 60°  

⇒ B = 60°- 45°

⇒ B = 15°  

Therefore,

The values of A = 45° and B = 15°

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