if sin(a+b) = √3/2 and tan a = 1 then angle b =
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If sin(A + B) = 1 and cos(A - B) = √(3)2 , 0^∘ B then find A and B .
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Given sin(A + B) = 1 sin(A + B) = sin 90^o ( sin 90^o = 1) A + B = 90^o ............ (1) Again, cos(A - B) = √(3)/2 cos (A - B) = cos 30^o ( cos ... More
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