Question

If sin (A+B)=√3/2and cos (A-B)=√3/2 then find the measure of the angles A and B ​

Answer 1

Answer:

The angle a = 45 and b=15

Answer 2

Answer:

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Step-by-step explanation:

Given sin(A+B)=1

⇒sin(A+B)=sin90° (∵sin90° =1)

⇒A+B=90°…………(1)

Again, cos(A−B)= 3/2

⇒cos(A−B)=cos30 o (∵cos30 = 3/2)

⇒A−B=30°…………(2)

Adding (1)+(2)

A+B+A−B=99°+30°

⇒2A=120°

⇒A=120/2

⇒A=60°

Putting A=60° in equation-(2) we get

A−B=30°

⇒60°−B=30°

⇒60°−30° =B

⇒B=30°

∴A=60° ;B=30° .