Math, asked by nidhiojha6427, 1 year ago

If sin(a-b)=3/5,sin(a+b)=4/5 and sin[(a+b)+(a-b)]=sin[(a+b)cos(a-b)+cos(a+b)sin(a-b)], then find the value of sin2a

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Answered by Ravispssbp

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