if sin a+b = √3 and cos a-b = 0 then find the value of a and b
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Step-by-step explanation:
sin(A+B)=1
cos(A-B)=√3/2
We know sin-¹ =90
A+B=9 _ _ _ _(1)
cos (A-B)=root 3/2
A-B=cos-¹ root 3/2
We know cos-¹ root 3/2=30
A-B=30 _ _ _ _ _ (2)
Solve (1) & (2)
A+B=90
A-B=30 add
2A=120
A=60 B=30
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raedabdulrasheed:
Pls mark it as the Brainliest answer if it helps you, @arshad58
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