Question

If sin=a/b find cos and cot

Answer 1

Solution:

Given sinA = a/b---(1)

i) cos²A = 1-sin²A

= 1- (a/b)²

= 1- a²/b²

= (b²-a²)/b²

cosA = √(b²-a²)/b ---(2)

ii) cotA = cosA/sinA

= [√(b²-a²)/b]/(a/b)

= √(b²-a²)/a---(3)

••••

Answer 2

sin = $\frac{a}{b}$

cos = $\frac{1}{sin}$ = $\frac{1}{a/b}$

= $\frac{b}{a}$

cot = $\frac{sin}{cos}$ = $\frac{a/b}{b/a}$

= $\frac{a^2}{b^2}$

Hope it helps!!!

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