Question

if sin a + b is equals to 1 and Cos A + B is equals to root 3 by 2 whereas a is Lesnar then b find the value of B​

Answer 1

Answer:

Step-by-step explanation:sin(a+b)=1

sin(a+b)=sin90

a+b=90

cos(a-b) =cos30

a-b=30solving this a=60 b=30

Answer 2

$\bold{question \: } :$

$sin(a + b) = 1 \: and \: cos(a - b) = \frac{ \sqrt{3} }{2}$

So we need to find the values of both a and b

So let us start

$= > sin(a + b) = 1 \\ \\ = > sin(a + b) = sin90 \degree \\ \bold{cancelling \: sin \: on \: both \: sides} \\ \\ = > a + b = 90....(1)$

And

$= >cos(a - b) = \frac{ \sqrt{3} }{2} \\ \\ = > cos(a - b) = cos30 \degree \\ \bold{ cancelling \: cos \: on \: both \: sides} \\ \\ = >a - b = 30....(2)$

Now eq (1)-(2)

$= > (a + b = 90) - (a - b) = 30 \\ \\ = > 2b = 60 \\ \\ = > b = 30$

So by putting the value of b in eq (1) we can calculate out the value of a

so ,b=30

•°• a+b=90

=> a= 60