Question

if sin(a+b)=root 3/2, and cos A-B= 1, 0° <A+B<90°, A =>B, find A and B​

Answer 1

Step-by-step explanation:

$sin(a + b) = \sqrt{ \frac{3}{2} } \\ \\ (a + b) = sin60 \\ \\ (a + b) = 60.....(2) \\ \\ \\ cos(a - b) = 1 \\ \\ (a - b) = cos0 \\ \\ (a - b) = 0.....(2) \\ \\ \\ equation \: (1) \: and \: (2) \\ \\ a + b = 60 \\ \\ a - b = 0 \\ = = = = = = = = = = \\ \\ 2a = 60 \\ a = 30 \\ \\ a = 30put \: in \: equation \:( 2) \\ \\ a - b = 0 \\ \\ 30 - b = 0 \\ \\ - b = - 30 \\ \\ b = 30 \\ \\ \\ a = 30 \\ b = 30$