Math, asked by manojkumar292, 5 months ago

if sin (A+B) =root 3/2 where 0<A+B<90 A>B find A and B​

Answers

Answered by Sarena123
0

Step-by-step explanation:

Given sin(A+B)=1

⇒sin(A+B)=sin90o (∵sin90o=1)

⇒A+B=90o …………(1)

Again, cos(A−B)=3/2

⇒cos(A−B)=cos30o (∵cos30o=3/2)

⇒A−B=30o …………(2)

Adding (1)+(2)

A+B+A−B=90o+30o

⇒2A=120o

⇒A=120/2

⇒A=60o

Putting A=60o in equation-(2) we get

A−B=30o

⇒60o−B=30o

⇒60o−30o=B

⇒B=30o

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