if sin (A+B) =root 3/2 where 0<A+B<90 A>B find A and B
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Step-by-step explanation:
Given sin(A+B)=1
⇒sin(A+B)=sin90o (∵sin90o=1)
⇒A+B=90o …………(1)
Again, cos(A−B)=3/2
⇒cos(A−B)=cos30o (∵cos30o=3/2)
⇒A−B=30o …………(2)
Adding (1)+(2)
A+B+A−B=90o+30o
⇒2A=120o
⇒A=120/2
⇒A=60o
Putting A=60o in equation-(2) we get
A−B=30o
⇒60o−B=30o
⇒60o−30o=B
⇒B=30o
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