Math, asked by shravyashravya54, 7 months ago

If sin A+B =root 3by2, cos A-B = 1by2, 0degrees <A+B<90 degrees, A>B.find A and B


Answers

Answered by swapniltripathi91
1

A=60degree. and B =60 DEGREE. is the right answer

SinA+B=√3/2

so A+B=60

CosA-B=1/2

soA-B=60

so when you solve this equations by elimination method

Answered by kritee1239
1

Answer:

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