Question

If Sin(A+B) = SinA CosB - CosA SinB and Cos(A-B) = CosA CosB + SinA SinB, then find the value of Sin15° and Cos15°​

Answer 1

Answer:

cos(tan******sim cos tan theta 144^67*%990

Answer 2

Answer:

$⇒ sin \: 15° = \frac{ \sqrt{3} - 1}{2 \sqrt{2} }$

$⇒ cos \: 15° =  \frac{ \sqrt{3} + 1}{2 \sqrt{2} }$

Step-by-step explanation:

It is the correct answer.