If sin(A-B)= sinAcosB-cisAsinB and
Cos(A-B)= cisAcosB +sinAsinB
Find values of sin15 and cos 15
Detailed solution plz
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sin15=sin(45-30)=sin45cos30-cos45sin30
=1/√2×√3/2-1/√2×1/2=(√3-1)/2√2
in a similar way u can find cos 15 I.e. cos(45+30)
=1/√2×√3/2-1/√2×1/2=(√3-1)/2√2
in a similar way u can find cos 15 I.e. cos(45+30)
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hope, its will help u
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