Question

If sin(A+B)=sinAcosB+cosAsinB, find sin75°​

Answer 1

Step-by-step explanation:

sin 75° = sin(45°+30°)

where A = 45° and B = 30°

= sinA cosB + cosA sinB

= sin45° cos30° + cos45° sin30°

= 1/√2 × √3/2 + 1/√2 × 1/2

= √3/2√2 + 1/2√2

= (√3+1)/2√2