if sin A=¾, calculate cos A and tos A.
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Step-by-step explanation:
Given :-
Sin A = 3/4
To find :-
Calculate I) Cos A and ii) Tan A ?
Solution :-
Given that
Sin A = 3/4------------(1)
On squaring both sides then
=> (Sin A )² = (3/4)²
=> Sin² A = (3×3)/(4×4)
=> Sin² A = 9/16
=> 1 - Sin² A = 1 -(9/16)
=> 1 - Sin² A = (16-9)/16
=> 1 - Sin² A = 7/16
We know that
Sin² A + Cos² A = 1
=> Cos² A = 7/16
=> Cos A = ±√(7/16)
=> Cos A = ±√7/4
Since A is acute angle
Cos A = √7/4 --------------(2)
On dividing (1) by (2)
=> (1)÷(2)
=> Sin A / Cos A = (3/4)/(√7/4)
=> Tan A = (3/4)×(4/√7)
=> Tan A = (3×4)/(4×√7)
=> Tan A = 3/√7 or
=> Tan A = (3/√7)×(√7/√7)
=> Tan A = (3×√7)/(√7×√7)
=> Tan A = 3√7/(√7)²
=> Tan A = 3√7/7
Therefore , Tan A = 3/√7 or 3√7/7
Answer:-
The value of Cos A = √7/4
The value if Tan A = 3/√7 or 3√7/7
Used formulae:-
- Sin² A + Cos² A = 1
- Tan A = Sin A / Cos A
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