Question

If sin A- cos A =0, then the value of A is

Answer 1

Answer:

$\sin(a) = \cos(a) \\ \sin(a) = \sin(90 - a) \\ eliminate \: sin \: on \: both \: sides \\ a = 90 - a \\ a + a = 90 \\ 2a = 90 \\ a = 45 \: degrees$

Answer 2

Answer:

sinA-cosA=0

sinA=cosA

sinA=π\2 -A {sin(π\2-A)=cos}

so, A=π\2-A

A+A=π\2

2A=π\2

A=π\4