If sin A = cos A, 0° <A < 90°, then A is equal
to
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Angle a is equal to 45°
Step-by-step explanation
As we know that between 0° and 90 degrees so as the value of sine 45° this one by root two and also the value of cosine 45° is one by Route 2
There fore sine 45° and cos 45° at the only values that place as per angle a condition in the question which justifies the same angle that is -45° therefore angle a is equal to 45 degrees
Step-by-step explanation
As we know that between 0° and 90 degrees so as the value of sine 45° this one by root two and also the value of cosine 45° is one by Route 2
There fore sine 45° and cos 45° at the only values that place as per angle a condition in the question which justifies the same angle that is -45° therefore angle a is equal to 45 degrees
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