Question

If sin a- cos a=1/3. What is the value of sin 2A?show your solution​

Answer 1

Answer:

(sinA+cosA)^2=sin^ (2)A+cos^(2)A+2×sinAcosA

Sin^(2)A+cos^(2)A=1 by trigonometric identities also 2 sinA cosA =sin2A

And sinA+cosA=1 by given question

Therefore the equation becomes

Sin2A=1-1^(2)

Sin2A=0

2A=sin inverse(0) ( sin is zero for angles 0, pi,2 pi …npi)

Considering the least value ,A=0