If sin a + cos a =1, prove that sin a - cos a = +1.
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Answer:
sin a + cos a = 1
squaring both sides,
[ (a+b)² = a²+b²+2ab]
sin²a + cos²a + 2(sin a)(cos a) = 1
1 + 2(sin a)(cos a) = 1
2(sin a)(cos a) = 0 -------1
ATQ,
sin A - cos A = +1
squaring both sides,
[ (a-b)² = a²+ b² + 2ab ]
sin²A + cos²A - 2(sin a)(cos a) = 1
sin²A + cos²A - 0 = 1 [from EQ. 1]
(sin A - cos A)² = 1
[transfer root]
(sin A - cos A) = √1
sin A - cos A = ± 1
H.P.
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