If sin A + cos A = 1, then value of sin2A is
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=>sinA+cosA=1
squaring both the sides
=>(sinA+cosA)²=1²=1
=>sin²A+cos²A+ 2sinAcosA=1 [As,sin²A+cos²A=1]
=>1+2sinAcosA=1 [As2sinAcosA=sin2A]
=>sin2A=0
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