Math, asked by malayjmistry13, 7 months ago

if sin a + cos A = √2 sin (90 - A), then obtain the value of cot a​

Answers

Answered by sunakat483
0

Answer:

Given

sinA+cosA=

2

sin(90−A)

2

1

sinA+

2

1

cosA=sin(90−A)

⇒sinA.cos45

+cosA+sin45

=sin(90−A)

⇒(A+45

)=sin(90

−A)

Equating

A+45=90−A

⇒2A=45

⇒A=22

2

1

A=

8

π

∴cotA=cot

8

π

=

2

+1

Step-by-step explanation:

hope this will help you

Answered by ummadichanakya2007
0

Answer:

cot a = \frac{1}{\sqrt{2}-1}

Step-by-step explanation:

sin a +cos a = \sqrt{2} sin(90- a)

=>sin a + cos a = \sqrt{2} cos a

=>sin a = \sqrt{2} cos a- cos a

=>sin a = cos a (\sqrt{2} -1)

=>\frac{sin a}{cos a} = \sqrt{2} -1\\

=>\frac{1}{cot a} = \sqrt{2}-1

=>cot a = \frac{1}{\sqrt{2}-1}

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