Math, asked by zunaira36, 1 year ago

If sin A+cos A=3/2 then find the value of sum of all trigonometric ratios with angle A
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Answers

Answered by Anonymous
0

Answer:


Step-by-step explanation:

Step-by-step explanation:


Hi,


Given sin A + cos A = 3/2


Now squaring on both sides we get


sin²A + cos²A +2 sin A cos A = 9/4


⇒ 1 + 2 sin A cos A = 9/4


⇒2 sin A cos A = 5/4


⇒ sin A cos A = 5/8


Now,


Consider sin A + cos A + tan A + cot A + cosec A + sec A


= (sin A + cos A) + (sin A/cos A + cos A/sin A) + (1/sin A + 1/ cos A)


=(sin A + cos A) + (sin²A + cos²A)/sin A cos A + (sin A + cos A)/sin A cos A


= 3/2 + 8/5 + 8/5*3/2


= 3/2 + 8/5 + 12/5


= 11/2


Hope, it help


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