If sin A+cos A=3/2 then find the value of sum of all trigonometric ratios with angle A
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chordiasahil24:
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Answer:
Step-by-step explanation:
Step-by-step explanation:
Hi,
Given sin A + cos A = 3/2
Now squaring on both sides we get
sin²A + cos²A +2 sin A cos A = 9/4
⇒ 1 + 2 sin A cos A = 9/4
⇒2 sin A cos A = 5/4
⇒ sin A cos A = 5/8
Now,
Consider sin A + cos A + tan A + cot A + cosec A + sec A
= (sin A + cos A) + (sin A/cos A + cos A/sin A) + (1/sin A + 1/ cos A)
=(sin A + cos A) + (sin²A + cos²A)/sin A cos A + (sin A + cos A)/sin A cos A
= 3/2 + 8/5 + 8/5*3/2
= 3/2 + 8/5 + 12/5
= 11/2
Hope, it help
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