Math, asked by ujjwaljaat28, 9 months ago

If sin A = cos A, find the value of
2 tan² A-2 sec² A + 5.​

Answers

Answered by lethargic4
0

Answer:

3

Step-by-step explanation:

Sin A = cos A when A= 45°

so

2 tan^2 A - 2 sec^ 2 A +5

2(tan ^ 2 45° ) - 2 sec^2 45° +5

2(1)-2(√2)^2 + 5

2 - 2(2) +5

2-4+5

-2+5

=3

Answered by rohitrs0908
0

Answer:

Step-by-step explanation:

2 tan² A-2 sec² A + 5

2*1 - 2 sec² A +5 (tanA= sinA/cosA = 1)

7-2 sec²A

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