If sin A = cos A, find the value of
2 tan² A-2 sec² A + 5.
Answers
Answered by
0
Answer:
3
Step-by-step explanation:
Sin A = cos A when A= 45°
so
2 tan^2 A - 2 sec^ 2 A +5
2(tan ^ 2 45° ) - 2 sec^2 45° +5
2(1)-2(√2)^2 + 5
2 - 2(2) +5
2-4+5
-2+5
=3
Answered by
0
Answer:
Step-by-step explanation:
2 tan² A-2 sec² A + 5
2*1 - 2 sec² A +5 (tanA= sinA/cosA = 1)
7-2 sec²A
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