If sin A= Cos A,then find the value of 2tanA+cos^2A
abhaymoorthy:
It is given thatsinA = cosAthen=2tanA +cos^2A=2(sinA/cosA) + cos^2A=2(1)+ 1-sin^2A=3-sin^2Aalso;we know thatsin^2A+cos^2A=12sin^2A=1....[because sinA=cosA]sin^2A=1/2=3-(1/2)=3-(0.5)=2.5
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ur statement is wrong
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if sin a = cos a
=> a = 45°
=> 2 tan a + cos ² a
= 2 tan 45 + cos 45× cos 45
= 2 × 1 + (1/√2)²
= 2 + 1/2
= 5/2
=> a = 45°
=> 2 tan a + cos ² a
= 2 tan 45 + cos 45× cos 45
= 2 × 1 + (1/√2)²
= 2 + 1/2
= 5/2
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