if sin A + cos B = a and sin B + cos A = b, then sin (A+B) is equal to
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sinA cosB+cosA sinB
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sinA +coaB=a
cosB=a-sinA
sinB+cosA=b
sinB=b-cosA
now, sin(a+b)=sinAcosB+cosAsinB
=sinA(a-sinA) + cosA(b-cosA)
=asinA-sin^2A+bcosA-cos^2A
=asinA+bcosA-1
cosB=a-sinA
sinB+cosA=b
sinB=b-cosA
now, sin(a+b)=sinAcosB+cosAsinB
=sinA(a-sinA) + cosA(b-cosA)
=asinA-sin^2A+bcosA-cos^2A
=asinA+bcosA-1
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