Question

If sin a cos B then find the range of values of cos a sin B.​

Answer 1

Step-by-step explanation:

Given,

sinAcosB = -1/2 ... (1)

Let,

cosAsinB = x ... (2)

Adding (1) and (2)

sinAcosB + cosAsinB = -1/2 + x

sin(A + B) = -1/2 + x

As we know,

the range of any sin function is [-1,1]

Therefore,

-1 《 -1/2 + x《 1

-1 + 1/2 《 x 《 1 + 1/2

-1/2 《 x 《 3/2

x = [-1/2,3/2]