If sin A = cos B, then prove that A + B = 90º.
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Answered by
55
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SIN A = SIN (90-B)
= A+B= 90
HOPE HELPS ✌️✌️✌️
SIN A = SIN (90-B)
= A+B= 90
HOPE HELPS ✌️✌️✌️
Answered by
25
Answer:
Proved that A+B =90°
Step-by-step explanation:
It is given to us that Sin A =Cos B.
In that case, we have to prove that A+B =90°
Now, given expression, Sin A = Cos B
⇒ Sin A = Sin (90°-B)
Since, we know that Sin (n*90 - α) = Cos α, if n=1
=Sin α, if n=2
= -Cos α, if n=3 and
= -Sin α, if n=4
Hence, cancelling Sin from both sides, A= 90° - B, ⇒A+B = 90° (Proved)
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