If sin A = cos B, where A and B are acute angles then find A + B
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sinA=cos(90−A)
Given, \: sinA=cosBGiven,sinA=cosB
Cos B \: =cos(90−A)CosB=cos(90−A)
⇒B=90−A⇒B=90−A
⇒A+B=90⇒A+B=90
Hence, A+B=90Hence,A+B=90
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