If sin A+cosA=root 3 then prove that tanA+ CotA=1
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Solution :-
sin A + cosA = √3
A/Q
=> (sinA +cosA)² = sin²A + cos²A + 2sinA .cosA
=> (√3)²= 1 + 2sinA .cosA
=> 3 -1 = 2sinA .cosA
=> sinA .cosA = 1
then ,
=tanA + cot A
= sinA / cosA + cosA/ sinA
=(sin²A + cos²A )/ sinA . cosA
= 1 /1 = 1
hence , tan A + cot = 1 .
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