If sin A - cosB = 0, prove that A + B = 90°
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sinA - sin(90-B)=0
sin(A) -sin -(90-B)=0
A- 90 +B =0
A+ B = 90
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Answered by
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Trigonometry :
Given, sin A - cos B = 0
sin A = cos B
sin A = sin ( 90 - B )
A = 90 - B
A + B = 90°
navvi123:
Not appropriate
Yes.. Sorry for that. I changed the concept.
Its ok not everybody is perfect.
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