Question

if sin A + cosec A =2, then sin^19A + cosec^19A =​

Answer 1

Answer:

sinx+cosecx=2

⇒sinx+

sinx

1

=2

⇒sin

2

x+1=2sinx

⇒sin

2

x−2sinx+1=0

⇒(sinx−1)

2

=0

⇒sinx=1

cosecx=1

sin

10

x+cosec

10

x=2

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