If sin(a + iß) = x + iy then the value is equal to
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Sin (A+B) = Sin(A)Cos(B) + Sin(B)Cos(A)
Sin(a+ib) = Sin(a)Cos(ib) + Sin(ib)Cos(a)
which can be write as
Sin(a+ib) = Sin(a)Cosh(b)+i(Cos(a)Sinh(b))
which is of the form x+iy
Sin(a+ib) = = x+ iy where
x = Sin(a)Cosh(b)
y = Cos(a)Sinh(b)
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