Question

if sin a is 3/6 so what is trigonometry ratio of cos a​

Answer 1

Answer:

Step-by-step explanation:

SinA=3/6=P/H

Therefore P=3K, where k is unit

And, H=6K

Now, isong Pythagoras theorem,

(H) ²=(P) ²+(B) ²

(6K)²= (3K) ²+ (B) ²

36K²= 9K²+ B²

B²= 36K²-9K²

B²= 25K²

B=√25K²

B=5K

Therefore, cosA=B/H

5k/6k

This is the answer

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Answer 2

Given: sinA = 3/6

To find: cosA

Now, as, sinθ = Opp. side ÷ Hypotenuse

So, Accordingly;

Opposite side or Perpendicular = 3x

and,

Hypotenuse = 6x

Now, By Pythagoras Theorem;

H² = B² + P²

or B = √(H²−P²)

Thus, B = √((6x)²−(3x)²)

B = √(36x² − 9x²)

B = √27 x

∴ B = 3√3 x

Therefore, cosA = 3√3 x ÷ 6 x

or cosA =√3 / 2

∴ ∠ A = 30°