if sin a is equal to 1 by 3 X and 10 is equal to 1 by 3 then find the value of x square minus one by x square
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if sin a is equal to 1 by 3 x and tan a is equal to x/3 then find the value of x square minus one by x square
- Given sin A = 1/3x and tan A = x/3
- So tan A = x/3
- So sin A / cos A = x/3
- So 1/3x / cos A = x/ 3
- So 1/xcos A = x
- Now cos A = 1/x^2 ------------1
- So x^2 = 1/cos A
- Now we need to find the value of x^2 – 1/x^2
- = 1 / cos A – cos A
- = (1 – cos^2 A ) / cos A
- = sin^2A / Cos A
- = sin A. tan A
- = (1/3x) x x / 3
= 1 / 9
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