If sin A is equal to 3/4, find cos A and Tan A
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ANSWER:
Given,
SinA=3/4
SinA=Opp/hyp=3x/4x
By using Pythagoras theorem:
AC^2=AB^2+BC^2
(4x)^2=Ab^2+(3x)^2
AB^2=16x^2-9x^2
AB^2=7x^2
AB=root7x
CosA=adj/hyp=root7x/4x=root7/4
TanA=Opp/adj=3x/root7x=3/root7
Given,
SinA=3/4
SinA=Opp/hyp=3x/4x
By using Pythagoras theorem:
AC^2=AB^2+BC^2
(4x)^2=Ab^2+(3x)^2
AB^2=16x^2-9x^2
AB^2=7x^2
AB=root7x
CosA=adj/hyp=root7x/4x=root7/4
TanA=Opp/adj=3x/root7x=3/root7
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