If sin A = root 3 ÷ 2 and cos B = root 3 ÷ 2 . Find value of tan A - tan B ÷ 1 + tan A × tan B
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Answer:
as we know tan(A-B) =(tanA-tanB)/1+tanAtanB)
Step-by-step explanation:
- so tanA=sinA÷cosA. answer=0
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