if sin a =root3/2 find value of 2cot square a-1
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Hiii friend,
SinA = ✓3/2 = P/H
P = ✓3 and H = 2
By pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)² - (P)²
(B)² = (2)² - (✓3)²
(B)² = 4-3
B = ✓1 = 1
Therefore,
CotA = B/P = 1/✓3
2 × Cot² A - 1
=> 2 × (1/✓3)² -1
=> 2×1/3 -1
=> 2/3 -1 = 2-3/3
=> -1/3..Ans...
HOPE IT WILL HELP YOU....... :-)
SinA = ✓3/2 = P/H
P = ✓3 and H = 2
By pythagoras theroem,
(H)² = (B)² + (P)²
(B)² = (H)² - (P)²
(B)² = (2)² - (✓3)²
(B)² = 4-3
B = ✓1 = 1
Therefore,
CotA = B/P = 1/✓3
2 × Cot² A - 1
=> 2 × (1/✓3)² -1
=> 2×1/3 -1
=> 2/3 -1 = 2-3/3
=> -1/3..Ans...
HOPE IT WILL HELP YOU....... :-)
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3
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