Math, asked by kk5334473, 8 months ago


If sin a =
show that (3 cos a -4cos'a) = 0.
2.​

Answers

Answered by manjul19680
0

Answer:

incomplete question

Step-by-step explanation:

the value of sin a is not given

Answered by shashiguptaa
0

Answer:

Let theta be ₹.

sin ₹ = 1/2

sin ₹ = sin 30°

₹ = 30°

to prove:-

3cos₹ - 4cos^3₹ = 0

3cos30° - 4cos^3 30° = 0

3( \sqrt{3} /2) - 4( \sqrt{3} /2)^{3} = 03(

3

/2)−4(

3

/2)

3

=0

0 = 0

Hence Proved

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