If sin A + sin 2 A = x,
cos A + cos 2 A = y then cos A=
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Step-by-step explanation:
Substituting values
[(sinA+sin2A)2+(cosA+cos2A)2][(sinA+sin2A)2+(cosA+cos2A)2−3]
=[1+1+cosA−cos3A+cos3A+cosA][2+2cosA−3]
=(2+2cosA)(2cosA−1)
=4cosA−2+4cosA−2cosA
=4cos2A+2cosA−2
=2(2cos2A−1)+2cosA
=2cos2A+2cosA
=2(cosA+cos2A)=2y
Hence proved.
How satisfied
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