If sin a + sin ß = a and cos a + cos ß = b then
(A) 2cos (a - b) =a² + b2 – 2
(B) sin(a + b)
2ab
a² +6²
(C) sin (a + B)=a² + 62 – 2
(D)
cos (a -
B)
2ab
a +6²
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so here is the answer have a nice day
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