If sin A + Sin B = m and Cos A + Cos B = n .
Prove that :- Sin (A+ B) = 2mn / m²+n²
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Answer:use common sense
Explanation:
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for easy method
take
A=B=45°
sin A+sin B= m
1÷√2+ 1÷√2=m
√2=m
cos A+cos B=n
1÷√2+ 1÷√2=n
√2=n
given
R.H.S
2mn÷[m²+n²]
=2×√2×√2÷[(√2)²+(√2)²]
=2×2÷2+2
=4÷4
= 1
L.H.S
=sin (A+B)
=sin (45°+45°)
=sin 90°
=1
take
A=B=45°
sin A+sin B= m
1÷√2+ 1÷√2=m
√2=m
cos A+cos B=n
1÷√2+ 1÷√2=n
√2=n
given
R.H.S
2mn÷[m²+n²]
=2×√2×√2÷[(√2)²+(√2)²]
=2×2÷2+2
=4÷4
= 1
L.H.S
=sin (A+B)
=sin (45°+45°)
=sin 90°
=1
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