Question

if sin A +sin B +sin C =3 then possible value of cos A +cos B +cos C is​

Answer 1

Possible value will be cosA+ cosB+ cosC=0

Answer 2

Step-by-step explanation:

sin A +sin B +sin C =3

sin A +sin B +sin C = 1 + 1 + 1

=> sin A = 1 => A = 90

and sin B = 1 => B = 90

and sin C = 1 => C = 90

Now, cos 90 +cos 90 +cos 90

= 0 + 0 + 0

= 0.