Math, asked by Aynain, 4 months ago

If sin a + sin b + sin c = 3, what is cos a + cos b + cos c

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Answered by Sankalp050

Answer:

For normal incidence on a plane mirror identify which of these statements are true --

(I) Both the angles of incidence and reflection are 0 degree .

(II) Both the angles of incidence and reflection are 90 degree .

(III) The angles that both the incident ray and the reflected ray make with the mirror surface are 0 degree .

(IV) The angles that both the incident ray and the reflected ray make with the mirror surface are 90 degree ..

A) Only (I) is true .

B) Only (II) is true .

C) Both (I) and (III) are true .

D) Both (I) and (IV) are true ✔

Answered by sharukesh50

Answer:

d is correct

Step-by-step explanation:

Mark me as a brainlist

Aynain: Please look at my question in the beginning and answer

sharukesh50: sorry

sharukesh50: sinA+sinB+sinB=1+1+1

or. (sinA-1)+(sinB-1)+(sinC-1)=0………..(1)

Comparing the both sides of eqn. (1)

(sinA-1)=0. => sinA= 1 or A=90°

(sinB-1)=0 => sinB=1 or B=90°

(sinC-1)=0. => sinC=1 or C=90°.

Now cosA+cosB+cosC=?

Putting. A=B=C=90°

=cos90°+cos90°+cos90°

=0+0+0

= 0. Answer.

sharukesh50: this is your answer please check it

Aynain: Thanks

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If sin a + sin b + sin c = 3, what is cos a + cos b + cos c